This guy is an undercover shill for RS2 and he doesn't even know it.

Firstly, if you haven't already, scoot on over here and take a look at his derivation of tangential velocity.

Let me save you the suspense.

v = ω÷r

Yes, the

**inverse**of v = ω×r

Thus, r = ω÷v

But, the units! acceleration divided by length is velocity?

Of course, s ÷ t = 1

That's a given.

Multiplying an acceleration by a time yields a velocity (we all know that); conversely, dividing an acceleration by a length the same yields a velocity (we

*should*know that). It's all about how we want to scale the motion.

Therefore, a tangential velocity (1D) in proportion to an orbital acceleration (2D from our perspective) yields a real radius.

I see time.