Meeting a Terrific Challenge

Discussion of Larson Research Center work.

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Re: Meeting a Terrific Challenge

Post by dbundy » Tue Jul 10, 2018 2:58 pm

Hi Bruce,

Thanks again for your input. Thanks for sharing your take on the LST's Higgs boson in your 2012 post, which you link to above. I was out of the country at that point in time and not engaged in the LRC's theoretical development, though I heard the hoopla about it, even in Puerto Rico.

Your point about the spin 0 of the standard model Higgs boson is interesting. I made the comment that I was "tempted" to compare the RST's unit space/time progression to their concept of the Higgs, but actually, it's not even remotely possible, because the LST's theory of the standard model differs so fundamentally from the LRC's theory that any such comparison is pretty much impossible.

The LST community's theory of the standard model is posited to explain the relationships and properties of the model's content, but the content of the standard model is based on observation, on empirical data. My point is that, had Larson arrived at the same content and structure of the model, before the LST community did, it would have been tantamount to the "crucial experiment" that we've long talked about.

It's too late now, of course, but it's an interesting thought. Still, I think we can learn a lot from studying their theory, in spite of the huge differences in the foundations. It's unfortunate that their theory is a field theory, and that they explain the contents of the standard model as simply different excitations of those fields, including the Higgs field.

I don't think I could ever brook the notion that reality is founded in such an ad hoc fashion, after coming down from the world of awesome beauty and exhilaration, which Larson introduced us to, with his reciprocal system.

There's just no comparison. However, the fact that Larson developed his RSt the way he did, did not lead him to the observed contents of the standard model, but to his own model, with some unobserved contents.

Now, I have to qualify that, because the quarks and gluons of the LST's standard model are not directly observed either, but the existence of the quarks can be deduced from the LRC's RST-based theory. Not only that, but the division of the standard model's entities into two classes, fermions and bosons, by their peculiar properties, is easily shown, and we also can show why there are three sets, or families, of each, and no more.

There is more, but suffice it to say that the reason the LST theory needs the Higgs field is because each of the standard model entities has to have the property of quantum spin, integer spin for bosons and half-integer spin for fermions. Now, I'm not sure, but since the Higgs can decay into two photons, I would think that at least their helicities would be opposite, reflecting the 0 spin of the Higgs, but I have no idea.

What I do know is that the whole idea of their Higgs field giving mass to the particles of the standard model, emerges from the fact that fermions come in two versions - left handed and right handed, and to solve problems that arise as a result, they need the mass of the fermions to come from the Higgs field, not the EM or EW field.

Now, in our theory, we can plainly see that the chirality of the fermions arises from the reciprocity of the standard model contents. Futhermore, thanks to Larson's definition of force, which you alluded to, we don't have a need for autonomous forces such as the electromagnetic, weak and strong forces to explain why the atom has the characteristics it has.

Yet, we've barely scratched the surface. In particular, we are struggling with mass, but perhaps we can learn from your work, in this regard, which is quite impressive.

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Higgs Boson

Post by bperet » Thu Jul 12, 2018 9:26 am

Keep in mind that there are two factors missing from LST:
  1. No cosmic sector (3D time).
  2. No progression of the natural reference system at the atomic level.
The Higgs boson/field is their device to compensate for these missing factors.

This is somewhat revealing: wrote:If the Higgs field did not exist, particles would not have the mass required to attract one another, and would float around freely at light speed. Also, gravity would not exist because mass would not be there to attract other mass.
Just as astronomers had to conjure up "dark matter" and "dark energy" to account for these missing factors, physics has now had to conjure up their own version of "Higgs boson" and "Higgs field" to account for them at the atomic level--the "aether" of 19th century researchers.

The Higgs boson is a particle (cosmic, spatial rotation). When you take its conjugate by crossing the unit speed boundary, you end up with its nonlocal (wave) form, the Higgs field. Given my assumption that the Higgs boson is a kind of cosmic "rotational base," progression as an angular velocity moving at the speed of light, it is moving rotationally outward in time--and therefore its conjugate is a linear, inward motion in space--gravity--the Higgs field that gives particles their "mass," since mass is determined by the force of gravitational attraction.

This is how I see LST's interpretation of the Higgs system--not entirely accurate, as we know from Larson that gravitational motion is created by rotation in the time region, not the cosmic sector. But LST does not have a time region nor a cosmic sector, so they basically reinstate the 19th century aether "under new management."
Every dogma has its day...

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Re: Meeting a Terrific Challenge

Post by dbundy » Mon Jul 16, 2018 4:09 pm

Bruce wrote: they basically reinstate the 19th century aether "under new management."
I like that.

And I've always liked Larson's concept of gravity as the inward scalar motion of matter. It explains it so simply and elegantly, showing at once why it cannot be modified or screened off, and why it is limited in such a way as to permit the formation of solar systems and galaxies.

However, the inward scalar motion of Larson's rotating photons presents a contradiction in terms, since rotation in the material sector is not a scalar motion. In the RS2, the rotation is scalar, by definition, because the reciprocal in the displaced aspect is a natural rotation, when viewed from the opposite sector.

In the LRC's RSt, on the other hand, the photon doesn't rotate at all. It consists of two 3d oscillations, one of which is progressing in time only, while the other progresses in space only. Consequently, the combo (S|T or T|S unit), is massless initially, propagating at the speed of the unit (space/time) progression.

If these combos become unbalanced, through additions of S or T unit oscillations, the result depends on the configuration of the combo. Joining two 3d oscillations is similar to joining two soap bubbles. They partially interpenetrate one another, forming a one-dimensional axis between their points of origin. Adding a third "bubble," not on the 1d axis, forms a 2d plane from the lines between the origins and adding another one to that combination, not in the plane, forms a 3d volume from the lines between the origins.

Of course, with these three primitives, many perturbations can be formed by adding more "bubbles." (see here)

However, in the case of bubbles, every bubble is the same type of structure, so we can only take advantage of the analogy so far. In the case of space and time oscillations, the entities are reciprocal motion structures, which makes things even more interesting, given that the unit combos propagate at unit speed relative to a fixed reference system and that mass is defined as a property that slows down the speed of that propagation to less than unit speed.

It seems clear that adding S and/or T units to the 1d combos affects the frequency of the combo, since that operation adds space or time to the combo. The more units of time, relative to the units of space a combo has the lower its frequency and vice versa, the more units of space it has, relative to its units of time, the higher its frequency.

However, a special case arises, if three of these 1d combos are combined in such a way as to form a 2d combo. In this case, it's as if three sticks were joined end-to-end, forming a 2d plane, instead of a 1d stack of parallel sticks, forming a bundle. The bundle configuration is easy to combine with other bundles to form larger 1d bundles, but it's difficult to combine the 2d planes, not only because of the three vertices, but also because the two opposite "charges," at each vertex, constitutes a particular positive - negative orientation, that restricts how they can match up with another, identical plane.

Consequently, the bundles act like bosons and the triplets act like fermions, in general. Could this result be a coincidence? Maybe, but then, if we continue the development of the theory, we quickly see that, as far as 1d "charges" go, the combos we end up with all correspond to standard model entities (except for gluons and Higgs bosons) and no others.

We can go on from there, as we have shown, to find the chirality and parity of the combos, and this leads to plus and minus beta decay processes, as we have also shown. Can all this still be due to coincidence? It's highly doubtful, when you look at the consistency of the logic and the complexity of the result. It's a pretty compelling case for the reciprocal system.

However, a key part is missing that is a major element: the mass of the particles has not been accounted for. It's the same problem the LST community had for decades, as they sought to explain mass in terms of a field. Now that they're convinced that they have found the boson associated with the Higgs field, they are ecstatic. Yet, there's a caveat: most of the mass of the protons is not due to their quarks, in their theory, but it is due to the energy of the gluons.

These guys are very smart, and I am as dumb as a box of rocks, but I know from Larson (confirmed by Borg) that energy is not mass. A quantity of energy can be equivalent to a quantity of mass, but you can't just set the speed of light to 1, in Einstein's equation, and say, see? They are equal!

They are not equal, because mass is a three-dimensional quantity, while energy is a one-dimensional quantity, so there is an intrinsic difference, just as there is between 1d distance and 3d volume.

However, in the reciprocal system, while mass is 3d energy, with dimensions t3/s3, it is only the measure of 3d motion, with dimensions s3/t3. This is not the same for electrical charge, which is just a unit of 1d space, with dimensions of 1d motion, s/t, when moving.

Hence, the "charge" of our fermions increments from 0 to 3 (0 to -3), as units of space/time (time/space ) oscillation are added to the massless neutrino. One would think, then that, since the only difference between 3d motion and 1d motion is the number of dimensions involved, 3d mass would increment from 0 to 3 (0 to -3), just as "charge" does.

However, that is not the case since the down quark is the heaviest combo (4.8 Mev), followed by the up quark (2.3 Mev) and then, at a very distant third, the electron (positron) (.511 Mev). Why is this order of magnitude the reverse of the charge order?

Well, obviously because, while the 3d motion of the combos does increase from neutrino to electron (positron), that means the inverse of that motion, 3d energy, decreases, since they are reciprocals. Other factors enter in, but a quick glance at our RN equations, shows it plainly:

S|T = 3(1/2 + 1/1 + 2/1) = 12|12, for the neutrino;
S|T = (2/4 + 2/1+2/1) + 2(1/2+1/1+2/1) = 6|6 + 8|8 = 14|14, for the down quark;
S|T = (1/2 + 1/1+2/1) + 2(1/2+1/2+4/2) = 4|4 + 12|12 = 16|16, for the up quark, and
S|T = 3(2/4 + 2/1 + 2/1) = 18|18, for the electron (positron).

Analysis of the inner term of each particle, shows the down quark has one unit more of space oscillation than time oscillation (s/t = 2/1 + 2/2 = 4/3), while the up quark has two more units of time oscillation than space oscillation (s/t = 1/1 + 2/4 = 3/5), and the electron has 3 units more space than time oscillation (s/t = 6/3).

Of course, the polarity of the up quark is positive, which is what makes the "charges" of the proton combo work out, but it doesn't work out well for mass, since mass is not "charged" we might say.

Mathematically, at least, this is a lot like absolute values that have no polarity. If we remove the polarity for the 3d case, and add the numerator to the denominator of each inner term, as if we were to treat them in an absolute value sense, we get 4/3 = 7, 3/5 = 8 and 6/3 = 9, respectively.

Clearly, this is not going to get us to where we want to go, but it does show that the down quark, with the least added motion (1 unit), would have the most equivalent inverse motion (mass), the equivalent mass of the up quark would be less than that, because it possesses the next most motion (2 units), and the electron would be the least massive of all, because it has the most added motion (3 units).

To understand this, it helps to recall that we're dealing with the "seesaw" mechanism again. When the seesaw is balanced, as the three seesaws of the neutrino are, a pointer set in the center at the fulcrum point, pointing up to zero on a scale above, will move to the left or right when the seesaw is not balanced.

If we designate the units of the scale to the left of zero, as negative, and the those to the right as positive, then the pointer will indicate the left|right, or negative|positive, imbalance.

In our case, the neutrino is balanced, or zero, the down quark is -1, the up quark is -2 and the electron is -3 (the same holds for the antiparticles, but with opposite polarity).

Because, we are assuming, for the moment, that, in the case of 3d magnitudes, only the absolute values enter into the physical situation, unlike in the 1d case, the masses of the particles and antiparticles are the same, while their charges are opposite.

Admittedly, it's not much, but it's a start.

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