Derivation of s/t = 1

Discussion concerning the first major re-evaluation of Dewey B. Larson's Reciprocal System of theory, updated to include counterspace (Etheric spaces), projective geometry, and the non-local aspects of time/space.
Post Reply
User avatar
user737
Posts: 196
Joined: Wed Oct 24, 2018 7:39 pm
Location: In your head

Derivation of s/t = 1

Post by user737 »

This is not meant to be a formal definition.
That is beyond me at this point in my development.
There exists the distinct possibility this derivation is wrong and/or false (hope not!).
Please check my work.

Simple integration over time yields this Newtonian classic:
v (s/t) = a (s/t2) × t

Given:

acceleration (a) = 10 m/s2
distance (x) = 250 m
time (t) = 5 s

Solve:

velocity (normalized to time): vt = a × t = 10 m/s2 × 5 s = 50 m/s
velocity (normalized to distance): vx = a ÷ x = 10 m/s2 ÷ 250 m = 0.04 s-2

These, of course, are averages as we are dealing with acceleration, or change in velocity over time (or conjugate velocity as change in energy, our "forcing function" [Ed: lulz], over distance).

If we multiply an acceleration by a time, we get a velocity (s/t2 × t = s/t → v)... magnitude, no direction.

If we divide an acceleration by a distance, we also get a velocity... but how can this be? The units don't work? Or do they...

Yes, inverse seconds squared is an equivalent velocity. We define it directly as 1/t2 being the equivalent motion inside unit space (the Time Region) and so being an angular velocity is a velocity nonetheless. This is the basis for the second power relationship in moving from the first to second equivalent dimension of motion (linear velocity, v → orbital velocity, v2).
  • In Case 1 (velocity normalized to time) -- MOTION IN SPACE or SPEED -- we do this all the time and is our standard practice. 50 m/s is 50 meters per 1 second. We have normalized time (to unity) by setting 1 = 5 seconds.
  • Conversely, in Case 2 (velocity normalized to distance) -- MOTION IN COUNTERSPACE or ENERGY -- we invert our operation (as we also invert our operand, i.e. space for time) where we then normalize distance (to unity) by setting 1 = 250 meters. This is only valid if what is stated above is true. i.e. we take inverse time to the second power to indeed be an equivalent velocity.
In either case we're simply creating a ratio (defining a motion or change).

In the case we are most familiar (Case 1), we create that ratio by normalizing to time and not to space as this is the ordinary bias that forms our perception of 4D space -- three dimensions of coordinate (extension) space plus one dimension of clock time (net effect of conjugate sector).

Therefore:

acceleration (spacial): ax = vx × x = 0.04 s-2 × 250 m = 10 m/s2
acceleration (temporal): at = vt ÷ t = 50 m/s ÷ 5 s = 10 m/s2

Sidebar: temporal acceleration would be the conjugate of spacial acceleration and therefore would be our "causal" "force" (in actuality just another aspect of motion and neither causal nor a-causal in its own right).

Assert:

a = at = ax = 10 m/s2

Ergo:

vx × x = vt ÷ t

but vx = vt as the kinetics described remain the same, we only change our perspective -- there it is again... that observer principal -- of motion (and have shown in both cases to have created an equivalent motion, either temporal or spacial)

so 1 × x = 1 ÷ t

or

x ÷ t = 1

put otherwise, F = ma :lol:
Why mass though? Why is mass the fulcrum?
Is this an inherent bias from our spacial viewpoint? It must be as mass ceases to have traditional meaning outside of a larger gravitational field (i.e. 3D space with clock time). Would its conjugate be the Aether?
More questions than answers.

"Thanks to Einstein and others, we know that time and distance are equivalent and interchangeable, in many ways." - Miles Mathis
Infinite Rider on the Big Dogma
User avatar
bperet
Posts: 1501
Joined: Thu Jul 22, 2004 1:43 am
Location: 7.5.3.84.70.24.606
Contact:

Re: Derivation of s / t = 1

Post by bperet »

user737 wrote: Sat Apr 27, 2019 1:45 pm Why mass though? Why is mass the fulcrum?
Is this an inherent bias from our spacial viewpoint? It must be as mass ceases to have traditional meaning outside of a larger gravitational field (i.e. 3D space with clock time). Would its conjugate be ether?
More questions than answers.
If you read the work of Gustave LeBon (1907, The Evolution of Matter), you find that he considers mass to be make-believe quantity that has no real meaning. He uses weight, t2/s2, instead. Mass is analogous to weight in motion (weight / speed).

I find this a much better way to look at it, particularly since weight has the same dimensions as magnetism--what atoms are made of in the RS.
Every dogma has its day...
Post Reply