4Be8 unstability

Discussion concerning the first major re-evaluation of Dewey B. Larson's Reciprocal System of theory, updated to include counterspace (Etheric spaces), projective geometry, and the non-local aspects of time/space.
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silvio.caggia
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4Be8 unstability

Post by silvio.caggia »

Let me recycle a question from Wladimir Guglinsky to mainstream phisics to ask if RS2 has an answer:
"All the even-even nuclei with Z=N are stable,
except the 4Be8.
There is not explanation for the unstability of the
4Be8 by considering the current models of the
Standard Nuclear Physics.
How do you explain why 4Be8 is not stable?"
Regards
Silvio
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bperet
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Beryllium instability

Post by bperet »

There is not explanation for the unstability of the

4Be8 by considering the current models of the

Standard Nuclear Physics.

How do you explain why 4Be8 is not stable?
Assuming you are familiar with atomic structure in the RS (electric and magnetic rotations, no protons, neutrons or electrons), and referring to Chapter 24, "Isotopes," in Basic Properties of Matter, the only time an atom is "stable" is when the magnetic ionization level of the environment is zero, in which case the atomic mass will be exactly twice the atomic number for all elements. Larson estimated our magnetic ionization level at 1 unit, and Table 35 (page 265) has the resulting isotopic mass values. Because of the unit magnetic ionization, NONE of the atoms are "stable" but only have a "zone of isotopic stability," described by Equation 24-1. This is why atomic mass is not just an integer (2Z+G)--it is the average mass of the atoms across the zone of stability--not the mass of every, individual atom, which will be in the 2Z+G range. (If you read an old paper I did on Subatomic Mass, Recalculated, it shows how the proton is actually a 50/50 split of charged and uncharged protons--an average).

Larson refers to this additional mass past the 2Z limit as "gravitational charge" (the G). Larson bases his initial calculations on the magnetic rotation only (the magnetic spin) and he does not include the electric rotation, as it is fairly insignificant for the heaver elements. (He was not after an exact work, but a general theory.)

If one were to include the mass effects of electric rotation, it would be limited to the atoms that have a single magnetic displacement in the subordinate magnetic rotation, which would be the 2-1-x range. Namely lithium (2-1-1), beryllium (2-1-2) and boron (2-1-3). Carbon and higher tends toward the more stable 2-2-(x) structure.

To measure the magnetic mass, you have to cross the regional boundary to get the rotation out of the time region by dividing by the inter-regional ration, so that is where the m02/156.4444 comes from, in Equation 24. Electric rotation is already outside the time region, so you don't have to do that transformation and any non-zero electric displacement will just add a single mass unit to the zone of stability. When you reach carbon, the more probably magnetic structure is 2-2-(4) which would require a significantly larger electric displacement to have any gravitational charge effect.

So for elements 3, 4 and 5, the zone of isotopic stability would be 2Z+G+1, where G=0 (floor of .06, .10, .16, since the RS is based on discrete units). That would make the zone of isotopic stability for lithium at 7 (observed 6.94), beryllium at 9 (observed 9.0121) and boron at 11 (observed 10.81). Remembering that the atomic mass is an average--not the mass of every, individual atom, so you are looking at a distribution of 2Z to 2Z+1.
Every dogma has its day...
oreneorg
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Joined: Thu Sep 22, 2016 12:58 pm

8Be

Post by oreneorg »

Discontinuity Beryllium is a continuity in the diagram where the zigzag Segre seen in items I like proton neutron number.

La discontinuidad del Berilio es una continuidad en el diagrama de Segré en donde se aprecia ese zigzag en los elementos de igual numero neutronico que protonico.

Very interesting theory ring Wladimir Guglinsky considering the Coriolis force would explain how they can interpenetrate two atoms of deuterium to give one of tritium, beating nuclear forces in the cold fusion.

muy interesante la teoria del anillo de Wladimir Guglinsky, teniendo en cuenta la fuerza de Coriolis que explicaria como se pueden interpenetrar dos atomos de Deuterio para dar uno de tritio, venciendo las fuerzas nucleares,en la fusión fria
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