Planck's Constant

Discussion concerning the first major re-evaluation of Dewey B. Larson's Reciprocal System of theory, updated to include counterspace (Etheric spaces), projective geometry, and the non-local aspects of time/space.
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bperet
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Planck's Constant

Post by bperet »

Wikipedia wrote:
The Planck constant (denoted h) is a physical constant that is used to describe the sizes of quanta.
The well-known use of the Planck constant is to relate the energy of a wave to its frequency: E = hv, where 'v' is the frequency in cycles per second and "cycles" are considered unitless. This gives Planck's constant the units of action, t2/s, which Larson states is not a "real quantity". Like most physical constants, it's just a catch-all when they don't understand the actual units involved.

Another form is to use: E = n ħ w, were ħ is the reduced Planck constant, h/2π, n is a natural number, and w is a velocity in radians per second. But let's not take shortcuts, and put the equation in its non-reduced form, keeping the radial measure: E = n h w 1/2π, and examine the components:

E = t/s, energy. One of the basics of the RS.

w = angular VELOCITY, a speed, having units of s/t. An important consideration here is that w is measured in "radians per second", so "radians" must have units of SPACE.

2π is not normally considered to have units, being a factor in the reduction of the Planck constant. I deliberately split it out from the common reference of h/2π as a separate item, because it is not just "2π", it is 2π RADIANS--it also has units of SPACE.

'n' is a natural number (scalar), having no units and just signifies a quantity. But is this the case? In a Universe of Motion, there are no unitless quantities, since everything can be reduced to units of motion. 'n' here is NOT unitless, but a measurement of LENGTH, in this case, the length of a Turn in counterspace, and also has units of SPACE.

What if, rather than association 2π with h, we associated it with w?

E = h n(w/2π)

It can be seen that w/2π = v, the conversion from radians/second to cycles/second. “Cycles” disguises the fact that there are other units of space involved, since it is normally a unitless quantity.

The units for n/2π are both space, giving them the appearance of being unit-less, so n(w/2π) simply reduces to units of speed, s/t.

If we plug in the space-time units, 'h' takes on a different meaning:

E (t/s) = h (t2/s2) n (s) w (s/t) / 2π (1/s)

The Planck constant now has units of momentum, and w has units of speed, just as Nehru stated in his derivation paper, but without the assumption of s/t = t/s.

If we plug in unit angular velocity of "1", which is one natural unit of turn, the Energy is its reciprocal, 2π/1 = 2π. (The quanta of counterspace is the wavelength, 2π radians.) The minimum quantity for n, being a natural number, is 1. Plugging in these values and solving for h:

h = E 2π/(nw)

= (1 * 2π) / (1 * 1)

= 2π

In Natural units, the value of the Planck constant is 2π, with units of momentum, and the reduced Planck's constant, ħ (h/2π = 2π/2π) is UNITY.

As is known from Larson's works, unit values are indicative of the progression of the natural reference system...

So, the Planck constant is the MOMENTUM of the progression of the natural reference system, and its use in E = nhv gives the energy of a photon of a specific frequency that is being carried by that progression, which is exactly how photons work in the RS.

To calculate its conventional value, one would have to go back to Nehru's paper on the topic, which is describing the process of how various assumptions made by the observer will view and measure the momentum of progression.

(Edited with suggestions/corrections provided by F.V. of the European Space Agency)
Every dogma has its day...
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Planck energy is magnetic to electric conversion

Post by bperet »

When I wrote this topic, I had not run across the concept of a "quantum pi" yet... but look at what it does:

E = h f

E = 2π f, where π = 4, so E = 8 f. Since h has the dimensions of momentum, a 2nd power function, it is referring to a magnetic rotation and E, energy, is an electric rotation, so what the equation says is that there are 8 electric units per magnetic unit.

Of course, we already knew that from Larson!
Every dogma has its day...
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